{"id":433417,"date":"2023-10-01T18:56:46","date_gmt":"2023-10-01T16:56:46","guid":{"rendered":"https:\/\/www.ecinews.fr\/?p=433417"},"modified":"2023-10-01T18:56:46","modified_gmt":"2023-10-01T16:56:46","slug":"digikey-lance-le-tirage-au-sort-back2school-2023","status":"publish","type":"post","link":"https:\/\/www.ecinews.fr\/fr\/digikey-lance-le-tirage-au-sort-back2school-2023\/","title":{"rendered":"DigiKey lance le tirage au sort Back2School 2023"},"content":{"rendered":"<h3><span style=\"font-size: 16px;\"><a href=\"https:\/\/www.digikey.fr\/?utm_source=referral&amp;utm_medium=pressrelease&amp;utm_campaign=pressrelease\">DigiKey<\/a> a annonc\u00e9 son populaire\u00a0<a href=\"https:\/\/www.digikey.fr\/fr\/resources\/social\/back2school?utm_source=referral&amp;utm_medium=pressrelease&amp;utm_campaign=pressrelease\">tirage au sort annuel Back2School<\/a>, qui offre aux \u00e9tudiants une chance de gagner un cr\u00e9dit DigiKey qu&rsquo;ils peuvent utiliser pour acheter des produits afin de cr\u00e9er et concevoir la prochaine g\u00e9n\u00e9ration de solutions.<\/span><\/h3>\n<p>9\u00a0prix seront distribu\u00e9s au total, et les gagnants seront s\u00e9lectionn\u00e9s au hasard. Le gagnant du premier prix recevra 1000\u00a0USD de cr\u00e9dit DigiKey, les trois gagnants du deuxi\u00e8me prix recevront 500\u00a0USD de cr\u00e9dit DigiKey et les cinq gagnants du troisi\u00e8me prix recevront 250\u00a0USD de cr\u00e9dit DigiKey.<\/p>\n<p>\u00ab\u00a0Nous sommes ravis de lancer le tr\u00e8s attendu tirage au sort Back2School\u00a02023 et de fournir aux \u00e9tudiants les outils, les produits et les ressources n\u00e9cessaires pour les aider \u00e0 progresser, non seulement en cours mais \u00e9galement pour leurs projets de conception en dehors de l&rsquo;\u00e9cole\u00a0\u00bb, a d\u00e9clar\u00e9 Y.C.\u00a0Wang, directeur du programme acad\u00e9mique mondial chez DigiKey. \u00ab\u00a0DigiKey s&rsquo;engage \u00e0 soutenir les \u00e9tudiants du monde entier pour les aider \u00e0 d\u00e9velopper des solutions nouvelle g\u00e9n\u00e9ration.\u00a0\u00bb<\/p>\n<p>Le tirage au sort est ouvert \u00e0 tous les \u00e9tudiants qui disposent d&rsquo;une adresse e-mail universitaire ou rattach\u00e9e \u00e0 un \u00e9tablissement d&rsquo;enseignement sup\u00e9rieur, et les participations peuvent \u00eatre envoy\u00e9es dans la langue locale de chaque \u00e9tudiant. Pour en savoir plus ou pour participer au tirage au sort Back2School, consultez le\u00a0<a href=\"https:\/\/www.digikey.fr\/fr\/resources\/social\/back2school?utm_source=referral&amp;utm_medium=pressrelease&amp;utm_campaign=pressrelease\">site Web de DigiKey<\/a>. Les participations sont ouvertes du 5\u00a0septembre au 30\u00a0octobre\u00a02023, et le nom des gagnants sera annonc\u00e9 le 15\u00a0novembre\u00a02023.<\/p>\n<p><a href=\"https:\/\/www.digikey.fr\/\">digikey.fr<\/a>\u00a0<\/p>\n","protected":false},"excerpt":{"rendered":"<p>DigiKey a annonc\u00e9 son populaire\u00a0tirage au sort annuel Back2School, qui offre aux \u00e9tudiants une chance de gagner un cr\u00e9dit DigiKey qu&rsquo;ils peuvent utiliser pour acheter des produits afin de cr\u00e9er et concevoir la prochaine g\u00e9n\u00e9ration de solutions. 9\u00a0prix seront distribu\u00e9s au total, et les gagnants seront s\u00e9lectionn\u00e9s au hasard. Le gagnant du premier prix recevra [&hellip;]<\/p>\n","protected":false},"author":36,"featured_media":433418,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"footnotes":""},"categories":[886],"tags":[],"domains":[47],"ppma_author":[1154],"class_list":["post-433417","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-news-fr","domains-electronique-eci"],"acf":[],"yoast_head":"<title>DigiKey lance le tirage au sort Back2School 2023 ...<\/title>\n<meta name=\"description\" content=\"DigiKey a annonc\u00e9 son populaire\u00a0tirage au sort annuel Back2School, qui offre aux \u00e9tudiants une chance de gagner un cr\u00e9dit DigiKey qu&#039;ils peuvent utiliser...\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" 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